How to solve the Josephus Problem?
A Puzzling Survival Game
Do you like puzzles and mathematical problems?
Then, get ready to play the Josephus game! It's a game of survival where the winner is the last person standing.
Consider N people standing in a circle. Every K-th person is eliminated until only one person remains. The task is to find the last person.
We use a recursive function that calculates the position of the survivor in a circle of N people, with every K-th person being eliminated.
1. Step 1:
If N == 1, return 1.
2. Step 2:
Else, return (josephus(N – 1 , K) + K – 1) % N + 1.
Curious to see it in action?
Simplify the Josephus problem with a list approach! Initialize a list of integers from 1 to N, then repeatedly remove the K-th element until only one remains.
If N is even, all even positions get deleted leaving N/2. The solution?
josephus(2 * N, 2) = josephus(N, 2) - 1
And for N odd? Find out by clicking here!
A Game Changer!
Click on the link below to start your journey.
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