Given three integers **A**, **B** and **C**, where **A** represents **n**, **B** represents **r** and **C** represents **p**

and **p** is a prime number greater than **n**, find and return the value of **nCr % p** where

**nCr % p = (n! / ((n-r)! * r!)) % p**.

**x!** means factorial of **x** i.e. **x! = 1 * 2 * 3… * x**.

**Input Format**

```
The first argument given is the integer A ( = n).
The second argument given is the integer B ( = r).
The third argument given is the integer C ( = p).
```

**Output Format**

```
Return the value of nCr % m.
```

**Constraints**

```
1 <= A <= 10^6
1 <= B <= A
A <= C <= 10^9 + 7
```

**For Example**

```
Input 1:
A = 5
B = 2
C = 13
Output 1:
10
Input 2:
A = 6
B = 2
C = 13
Output 2:
2
```

NOTE:You only need to implement the given function. Do not read input, instead use the arguments to the function. Do not print the output, instead return values as specified. Still have a doubt? Checkout Sample Codes for more details.

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