Problem Description
Given an integer array A of size N. You need to count the number of special elements in the given array.
A element is special if removal of that element make the array balanced.
Array will be balanced if sum of even index element equal to sum of odd index element.
1 <= N <= 105
1 <= A[i] <= 109
First and only argument is an integer array A of size N.
Return an integer denoting the count of special elements.
Input 1:
A = [2, 1, 6, 4]
Input 2:
A = [5, 5, 2, 5, 8]
Output 1:
1
Output 2:
2
Explanation 1:
After deleting 1 from array : {2,6,4} (2+4) = (6) Hence 1 is the only special element, so count is 1
Explanation 2:
If we delete A[0] or A[1] , array will be balanced (5+5) = (2+8) So A[0] and A[1] are special elements, so count is 2.
NOTE: You only need to implement the given function. Do not read input, instead use the arguments to the function. Do not print the output, instead return values as specified. Still have a question? Checkout Sample Codes for more details.