Given a string s, partition s such that every string of the partition is a palindrome.
Return all possible palindrome partitioning of s.
For example, given s = "aab"
,
Return
[
["a","a","b"]
["aa","b"],
]
Ordering the results in the answer :
Entry i will come before Entry j if :
- len(Entryi[0]) < len(Entryj[0]) OR
- (len(Entryi[0]) == len(Entryj[0]) AND len(Entryi[1]) < len(Entryj[1])) OR
*
*
*- (len(Entryi[0]) == len(Entryj[0]) AND … len(Entryi[k] < len(Entryj[k]))
In the given example,
["a", "a", "b"]
comes before ["aa", "b"]
because len("a") < len("aa")
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